![](imgs/right-triangle.gif) |
Right triangles have one 90° angle. Here,
there is an angle
and its corresponding opposite and adjeacent side.
The hypotenuse is always the side opposite of
the right angle.
Right triangles, their angles, and their sides,
can be solved using a set of ratios. Just remember: |
SOH CAH TOA |
This acronym stands for the ratios:
SOH: sin
= opposite side length ÷ hypotenuse length
CAH: cos
= adjacent side length ÷ hypotenuse length
TOA: tan
= opposite side length ÷ adjacent side
length |
So, given the following triangle,
find the side lengths: |
![](imgs/right-1550.gif) |
Since we know the angle, and we
know one side, we can solve the rest of the triangle.
Since sin
= opposite side length ÷ hypotenuse length,
we can set up the equation:
sin50° = x ÷ 15
sin50° * 15 = x
x =~ 11.49 |
![](imgs/right-155011.gif) |
Now we can solve the third side in
several different ways. You can use the pythagorean
theorem (a^2+b^2=c^2), you can use the cosine of
50°, or even the tangent of 50°. Let's solve
using the cosine: |
cos50° = x / 15
cos50° * 15 = x
x =~ 9.64 |
So now we have all three side lengths: |
![](imgs/right-1550119.gif) |
Think you got it? Try
the test! |